Number of options (potential timeslots), l=10
Number of required attendees, m=5
Average number of timeslot conflicts (rejections) per required attendee, r=3
Probability of finding a suitable time, 1-π0=%
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\[\pi_\gamma = \sum_{j=0}^{l-r-\gamma}\frac{(-1)^j l!}{j!\gamma!(l-\gamma-j)!} \left[\frac{(l-r)!(l-\gamma-j)!}{l!(l-r-\gamma-j)!}\right]^m \qquad \mathrm{(A13)}\]Based on Brown, Mathur, Narayan “Scheduling meetings: are the odds in your favo[u]r?” Eur. Phys. J. B 97 (120) 2024